Question: Multiply using partial products. Fill in the missing numbers. 767 × 7 _____ 420 + 49 _____

Multiply using partial products. Fill in the missing numbers.

767 × 7

420

• 49

Solution

To solve the problem using partial products, we multiply each digit of the top number by the bottom number and fill in the missing numbers. First, break down the multiplication: Multiply 7 by each digit in 767: 1. Multiply 7 by 7 (the hundreds place): \[ 7 \times 700 = 4900 \] 2. Multiply 7 by 6 (the tens place): \[ 7 \times 60 = 420 \] 3. Multiply 7 by 7 (the units place): \[ 7 \times 7 = 49 \] Add the partial products: \[ \begin{cases} 4900 & \\ 420 & \\ + 49 & \end{cases} \] Combining the results, we find: \[ 4900 + 420 + 49 = 5369 \] Therefore, the missing numbers are: First blank (700 section): 4900 Last blank (final result): 5369