Question: (\frac{2}{5} \times \frac{2}{7} = \frac{2}{15} \times \frac{3}{4} = \frac{3}{10} = 5\)…

\(\frac{2}{5} \times \frac{2}{7} = \frac{2}{15} \times \frac{3}{4} = \frac{3}{10} = 5\)

Solution

The photo contains three separate fraction problems. Let’s solve them one by one.

1. Problem 1:

   \[ \frac{2}{5} \times \frac{2}{7} \]

   Multiply the numerators:

   \[ 2 \times 2 = 4 \]

   Multiply the denominators:

   \[ 5 \times 7 = 35 \]

   So, the result is:

   \[ \frac{4}{35} \]

2. Problem 2:

   \[ \frac{2}{15} \times \frac{3}{4} \]

   Multiply the numerators:

   \[ 2 \times 3 = 6 \]

   Multiply the denominators:

   \[ 15 \times 4 = 60 \]

   Simplify the fraction \(\frac{6}{60}\):

   \[ \frac{6}{60} = \frac{1}{10} \]

3. Problem 3:

   \[ \frac{9}{10} \div 5 \]

   Rewrite the division as multiplication by the reciprocal:

   \[ \frac{9}{10} \times \frac{1}{5} \]

   Multiply the numerators:

   \[ 9 \times 1 = 9 \]

   Multiply the denominators:

   \[ 10 \times 5 = 50 \]

   So, the result is:

   \[ \frac{9}{50} \]