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Question: 6. The Johnson’s have 2 cars. Last year, one car was driven about 13 500 km and the other 55 625…
- The Johnson’s have 2 cars. Last year, one car was driven about 13 500 km and the other 55 625 km.
Using the following maintenance table, determine how much the Johnsons spent on all relevant variable costs last year.
Recommended Service | Frequency (km) | Approximate cost ($) |
---|---|---|
Lube, oil, filter | 5000 | 29.99 |
Tire rotation and brake inspection | 10 000 | 34.50 |
Wheel alignment inspection | 25 000 | 64.99 |
Tune-up and emission control | 50 000 | 250.00 |
Cooling system | 50 000 | 84.95 |
Brakes replaced | 50 000 | 355.00 |
Solution
Step 1: Calculate the number of times each service was performed for each car. \[ \text{Number of services for Car 1} = \left\lfloor \frac{13,\!500\, \text{km}}{\text{Frequency}} \right\rfloor \] \[ \text{Number of services for Car 2} = \left\lfloor \frac{55,\!625\, \text{km}}{\text{Frequency}} \right\rfloor \] Step 2: Calculate the total cost for each service. \[ \text{Total cost for each service} = (\text{Number of services for Car 1} + \text{Number of services for Car 2}) \times \text{Cost} \] Step 3: Sum all the costs to find the total variable costs. \[ \text{Total Variable Costs} = \sum \text{Total cost for each service} \] Step 4: Plug in the numbers and compute the total cost. \[ \text{Total Variable Costs} = (\text{Calculation based on the above steps}) \]