Question: (\[ (3 \times 6 + 7 - 9) \div 4 - 2 = 3 \] \[ 18 + 2 = 20 \] \[ 20 \div 4 - 2 = 5 - 2…

\(\[ (3 \times 6 + 7 - 9) \div 4 - 2 = 3 \]

\[ 18 + 2 = 20 \]

\[ 20 \div 4 - 2 = 5 - 2 \]\)

Solution

To solve the problem \((3 \times 6 + 7 - 9) \div 4 - 2\), follow these steps: First, calculate the expression inside the parentheses: \[ 3 \times 6 = 18 \] Then add and subtract the remaining numbers inside the parentheses: \[ 18 + 7 = 25 \] \[ 25 - 9 = 16 \] Now divide by 4: \[ 16 \div 4 = 4 \] Finally, subtract 2: \[ 4 - 2 = 2 \] The answer is \(2\).