Question: The length of Adamma’s rectangle is three times its width. What is the area of the rectangle, in…

The length of Adamma’s rectangle is three times its width. What is the area of the rectangle, in terms of the width?

Solution

The problem states: The length of Adamma’s rectangle is three times its width. What is the area of the rectangle, in terms of the width? Let the width of the rectangle be \( w \). The length of the rectangle is three times the width, so \[ \text{Length} = 3w \] The area \( A \) of a rectangle is given by the product of its length and width: \[ A = \text{Length} \times \text{Width} \] Substitute the expressions for length and width: \[ A = 3w \times w \] \[ A = 3w^2 \] Thus, the area of the rectangle in terms of its width is \( 3w^2 \).