Question: Solve for \( x \). \[ 9x + 9 \leq 27 \] \[ x \leq \boxed{?} \]

Solve for \( x \).

\[ 9x + 9 \leq 27 \]

\[ x \leq \boxed{?} \]

Solution

To solve the inequality \(9x + 9 \leq 27\), follow these steps: Subtract 9 from both sides of the inequality: \[ 9x + 9 - 9 \leq 27 - 9 \] Simplify: \[ 9x \leq 18 \] Divide both sides by 9: \[ x \leq \frac{18}{9} \] Simplify the fraction: \[ x \leq 2 \] Thus, the solution is \(x \leq 2\).