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Question: Consider the following polynomial. \[ s(x) = -7x^2 + 8x - 14 \] Step 2 of 2: Describe the…
Consider the following polynomial.
\[ s(x) = -7x^2 + 8x - 14 \]
Step 2 of 2: Describe the behavior of the graph of \( s(x) \) as \( x \to \pm \infty \).
Answer 4 Points
\[ s(x) \to \boxed{\phantom{as x \to -\infty}} \quad \text{as} \quad x \to -\infty \]
\[ s(x) \to \boxed{\phantom{as x \to \infty}} \quad \text{as} \quad x \to \infty \]
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Solution
Identify the leading term of the polynomial. \[ s(x) = -7x^2 + 8x - 14 \] The leading term is \(-7x^2\). Determine the end behavior based on the leading term. Since the coefficient of \(x^2\) is negative, the parabola opens downward. As \(x \to -\infty\), \(s(x) \to -\infty\). As \(x \to \infty\), \(s(x) \to -\infty\).