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Question: 5) Choose the best answer. Which table contains only values that are part of the solution set for…
- Choose the best answer.
Which table contains only values that are part of the solution set for \( y = 0.25x + 16 \)?
\[ \begin{array}{c|cccc} x & -8 & 0 & 8 & 16 \\ \hline y & -2 & 0 & 2 & 4 \end{array} \]
\[ \begin{array}{c|cccc} x & -8 & 0 & 8 & 16 \\ \hline y & 14 & 16 & 18 & 20 \end{array} \]
\[ \begin{array}{c|cccc} x & -8 & 0 & 8 & 16 \\ \hline y & -32 & 16 & 32 & 64 \end{array} \]
\[ \begin{array}{c|cccc} x & -8 & 0 & 8 & 16 \\ \hline y & 15.75 & 16 & 16.25 & 16.5 \end{array} \]
Solution
To solve this problem, we need to verify which table contains pairs \((x, y)\) that satisfy the equation \(y = 0.25x + 16\). Let’s check each option: Option 1: For \(x = -8\), calculate: \[ y = 0.25(-8) + 16 = -2 + 16 = 14 \] The given \(y\) is 8. This does not match. For \(x = 0\), calculate: \[ y = 0.25(0) + 16 = 0 + 16 = 16 \] The given \(y\) is 8. This does not match. This option does not match. Option 2: For \(x = -8\), calculate: \[ y = 0.25(-8) + 16 = -2 + 16 = 14 \] The given \(y\) is 14. This matches. For \(x = 0\), calculate: \[ y = 0.25(0) + 16 = 0 + 16 = 16 \] The given \(y\) is 16. This matches. For \(x = 16\), calculate: \[ y = 0.25(16) + 16 = 4 + 16 = 20 \] The given \(y\) is 20. This matches. For \(x = 24\), calculate: \[ y = 0.25(24) + 16 = 6 + 16 = 22 \] The given \(y\) is 22. This matches. This option matches all pairs. Option 3: For \(x = -8\), calculate: \[ y = 0.25(-8) + 16 = -2 + 16 = 14 \] The given \(y\) is -32. This does not match. This option does not match. Option 4: For \(x = -8\), calculate: \[ y = 0.25(-8) + 16 = -2 + 16 = 14 \] The given \(y\) is 15.75. This does not match. This option does not match. Therefore, the correct option is Option 2.