Question: (2) $2^{3x-2} = 64$

Solution

Step 1: Recognize that \(64\) is a power of \(2\). \[ 64 = 2^6 \] Step 2: Set the exponents equal to each other. \[ 3x - 2 = 6 \] Step 3: Solve for \(x\). \[ 3x = 8 \] \[ x = \frac{8}{3} \] Therefore, the solution is \(x = \frac{8}{3}\).